x^2+18=4x-40

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Solution for x^2+18=4x-40 equation: 



x^2+18=4x-40

We move all terms to the left:

x^2+18-(4x-40)=0

We get rid of parentheses

x^2-4x+40+18=0

We add all the numbers together, and all the variables

x^2-4x+58=0

a = 1; b = -4; c = +58;
Δ = b2-4ac
Δ = -42-4·1·58
Δ = -216
Delta is less than zero, so there is no solution for the equation

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